A) 48
B) 54
C) 96
D) 108
Correct Answer: D
Solution :
Here, \[\frac{AN}{2}=\frac{NB}{1}=\frac{AB}{3}\] \[\therefore \frac{NB}{AB}=\frac{1}{3}\] ?(1) As, \[\Delta BKN-\Delta BDA\] \[(A-A)\] So,\[\frac{ar.(\Delta BKN)}{ar.(\Delta BDA)}=\frac{{{(BN)}^{2}}}{{{(AB)}^{2}}}=\frac{1}{9}\] \[\Rightarrow ar.(\Delta BDA)=54\] \[\therefore ar(\Delta ABC)=108\]You need to login to perform this action.
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