A) 6.28 m
B) 3.14m
C) 0.95m
D) 5.25m
Correct Answer: B
Solution :
\[\vec{V}=(2\hat{i}+2\sqrt{3}\hat{j})\] \[\vec{B}=(10\sqrt{3}\hat{i}+10\hat{j})\] The time period of resolution \[T=\frac{2\pi m}{qB}\] The pitch of helix can be given by \[P=(4\cos {{30}^{o}})\times \frac{2\pi m}{qB}\] \[=4\times \frac{\sqrt{3}}{2}\times \frac{2\pi \times 10\sqrt{3}\times {{10}^{-6}}}{6\times {{10}^{-6}}\times 20}=\pi \]You need to login to perform this action.
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