A) \[-\frac{d}{4}\]
B) \[-\frac{d}{2}\]
C) \[-d\]
D) \[-2d\]
Correct Answer: B
Solution :
\[\int\limits_{0}^{2}{(4a{{x}^{3}}+3b{{x}^{2}}+2cx+d)dx=0}\] \[\Rightarrow \] \[a\cdot {{2}^{4}}+b\cdot {{2}^{3}}+c\cdot {{2}^{3}}+d\cdot 2=0\] \[\Rightarrow \] \[16a+8b+4c+2d=0\] \[\Rightarrow \] \[4a+2b+c=-\frac{d}{2}\]You need to login to perform this action.
You will be redirected in
3 sec