A) 0
B) 1
C) 2
D) infinite
Correct Answer: B
Solution :
\[\frac{\sin \theta }{\cos \theta +2}=\frac{1}{\sqrt{3}}\] \[\Rightarrow \] \[\sqrt{3}\sin \theta -\cos \theta =2\] \[\Rightarrow \] \[\sin \left( \theta -\frac{\pi }{6} \right)=1\] \[\Rightarrow \] \[\theta =\frac{2\pi }{3}\]You need to login to perform this action.
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