A) Both statements are True, Statement-2 explains Statement-1.
B) Both statements are True, Statement-2 does not explain Statement-1.
C) Statement-1 is True, Statement-2 is False.
D) Statement-1 is False, Statement-2 is true.
Correct Answer: A
Solution :
\[\frac{ydy}{\sqrt{1-{{y}^{2}}}}=dx\] \[\Rightarrow \] \[-\frac{1}{2}\cdot 2\sqrt{1-{{y}^{2}}}=x+c\] \[\Rightarrow \] \[-\sqrt{1-{{y}^{2}}}=x+c\] \[\Rightarrow \] \[{{x}^{2}}+{{y}^{2}}+2cx+{{c}^{2}}-1=0\] Centre of \[(-c,\,0),\] radius = 1.You need to login to perform this action.
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