A) 0.25 A
B) 1.2 A
C) 3.6 A
D) 1.6 A
Correct Answer: D
Solution :
According to energy conservation principle \[\frac{1}{2}m{{v}^{2}}=\frac{1}{2}L{{i}^{2}}\] \[\Rightarrow \,\,i=\sqrt{\frac{m}{L}}v=\sqrt{\frac{320\times {{10}^{-3}}}{2}}\times 4\] \[=4\times 4\times {{10}^{-1}}=1.6\,\,Amp\]You need to login to perform this action.
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