A) \[1.6\,{{\sec }^{-1}}\]
B) \[0.25\,{{\sec }^{-1}}\]
C) \[200\,{{\sec }^{-1}}\]
D) \[3.2\,{{\sec }^{-1}}\]
Correct Answer: D
Solution :
The potential energy of the system \[U=mV=4(200{{x}^{2}}+150)\] \[F=-\frac{dU}{dx}=-1600x\] \[\Rightarrow \,\,a=\frac{F}{m}=-400x\] Frequency of oscillation \[=\frac{\sqrt{400}}{2\pi }=3.2\,{{\sec }^{-1}}\]You need to login to perform this action.
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