JEE Main & Advanced Sample Paper JEE Main Sample Paper-2

  • question_answer
    \[\int_{{}}^{{}}{{{e}^{x}}\left( \frac{{{x}^{3}}-{{x}^{2}}+2x+1}{{{({{x}^{2}}+x+1)}^{2}}} \right)dx=}\]

    A)  \[{{e}^{x}}\left( \frac{x+1}{{{x}^{2}}+x+1} \right)+c\]    

    B)  \[{{e}^{x}}\left( \frac{x-1}{{{x}^{2}}+x+1} \right)+c\]

    C)  \[{{e}^{x}}\left( \frac{2x-1}{{{x}^{2}}+x+1} \right)+c\]  

    D)  \[{{e}^{x}}\left( \frac{2x+1}{{{x}^{2}}+x+1} \right)+c\]

    Correct Answer: B

    Solution :

    \[\int_{{}}^{{}}{{{e}^{x}}\left( \frac{{{x}^{3}}-1-{{x}^{2}}+2x+2}{{{({{x}^{2}}+x+1)}^{2}}} \right)dx}\] \[=\int_{{}}^{{}}{{{e}^{x}}\left( \frac{x-1}{{{x}^{2}}+x+1}+\frac{-{{x}^{2}}+2x+2}{{{({{x}^{2}}+x+1)}^{2}}} \right)dx}\] \[={{e}^{x}}\left( \frac{x-1}{{{x}^{2}}+x+1} \right)+c\]


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