JEE Main & Advanced Sample Paper JEE Main Sample Paper-30

  • question_answer
    When three progressive wave :  \[{{Y}_{1}}=4\sin (2x-6t),{{y}_{2}}=6\sin (2x-6t+\frac{\pi }{2})\] and \[{{Y}_{3}}=12\sin (2x-6t+\pi )\] are superimposed the amplitude of resultant wave is :

    A)  22 unit                                   

    B)  2 unit 

    C)  10 unit         

    D)  8 unit

    Correct Answer: C

    Solution :

    We can use the concept of vector addition to find resultant amplitude                   


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