A) \[{{53}^{o}}\]
B) \[{{127}^{o}}\]
C) \[106{}^\circ \]
D) \[90{}^\circ \]
Correct Answer: B
Solution :
The ray gets totally internally reflected at face AB as \[90{}^\circ -\theta >{{\theta }_{c}}={{\sin }^{-1}}\left( \frac{1}{\mu } \right)=37{}^\circ \] At face BC, it emerges out at grazing angle as shown in figure. The angle of deviation is \[\delta =180{}^\circ -(90{}^\circ -\theta )=90{}^\circ -\theta \] \[=90{}^\circ +37{}^\circ =127{}^\circ \]You need to login to perform this action.
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