A) 1
B) \[3/2\]
C) 2
D) 4
Correct Answer: C
Solution :
Vector \[\vec{a}\] and \[(\vec{a}\times \vec{b})\times \vec{a}\] are perpendicular \[\therefore \]Triangle is right angled. \[\sin 2A+\sin 2B+\sin 2C=4\sin A\sin B\sin C\] \[=4\sin A\sin C\] \[=2(cos\,(A-C)-\cos \,(A-C))\] \[=2\cos (A-C)\] \[\therefore \]Maximum value of sin 2A + sin 2B + sin 2C is 2.You need to login to perform this action.
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