A) \[3\times {{2}^{2}}\]
B) \[Yl/2A\]
C) \[Y{{l}^{2}}/2A\]
D) None
Correct Answer: A
Solution :
work \[=\int{Fdx=\int_{\,0}^{\,1}{\frac{AYx}{l}}dx}=\frac{AYl}{2}\]
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