JEE Main & Advanced Sample Paper JEE Main Sample Paper-30

  • question_answer
    The amplitude of a danyed harmonic oscillator become half in 3 second and will become \[1/x\] of the initial amplitude in next 6 second where \[x\] is:

    A) \[2\times 3\]                            

    B) \[{{2}^{2}}\]

    C) \[{{2}^{3}}\]        

    D) \[3\times {{2}^{2}}\]

    Correct Answer: C

    Solution :

    The variation in amplitude of a damped harmonic oscillator with time is given by: \[A={{A}_{0}}{{e}^{-bt}}\] \[{{A}_{0}}=\] initial amplitude, b = damping factor It is given that after 1 min. \[{{A}_{1}}={{A}_{0}}/2={{A}_{0}}{{e}^{-bt}}\] \[\therefore 2={{e}^{b}}\] \[\therefore \]After 3 min.         \[{{A}_{3}}={{A}_{0}}/x={{A}_{0}}{{e}^{-3b}}\] \[\therefore x={{e}^{3b}}={{2}^{3}}\]                         


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