A) \[2x-11y=15\]
B) \[2x+11y=15\]
C) \[2x+11y+15=0\]
D) \[11x-2y=15\]
Correct Answer: B
Solution :
PQ and QR making same angles with the tangent line at \[Q(2,1)\] \[\therefore \left| \frac{m-\frac{1}{2}}{1+m\cdot \frac{1}{2}} \right|=\left| \frac{2-\frac{1}{2}}{1+2\cdot \frac{1}{2}} \right|\] \[\left| \frac{2m-1}{m+2} \right|=\frac{3}{4}\Rightarrow m=2\] or \[\frac{-\,2}{11}\] Equation of QR is, \[(y-1)=\frac{-2}{11}(x-2)\] \[2x+11y=15\]You need to login to perform this action.
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