JEE Main & Advanced
Sample Paper
JEE Main Sample Paper-30
question_answer
When three progressive wave : \[{{Y}_{1}}=4\sin (2x-6t),{{y}_{2}}=6\sin (2x-6t+\frac{\pi }{2})\] and \[{{Y}_{3}}=12\sin (2x-6t+\pi )\] are superimposed the amplitude of resultant wave is :
A) 22 unit
B) 2 unit
C) 10 unit
D) 8 unit
Correct Answer:
C
Solution :
We can use the concept of vector addition to find resultant amplitude