A) \[1+\sqrt{3}\]
B) \[4-\sqrt{3}\]
C) \[2\sqrt{2}\]
D) \[4-\sqrt{2}\]
Correct Answer: A
Solution :
Let \[{{R}_{PQ}}={{R}_{eq}}\] Then \[{{R}_{RS}}={{R}_{eq}}\] The circuit can be redrawn as shown in below figure \[\Rightarrow {{R}_{eq}}=1+\frac{1\times {{R}_{eq}}}{1+{{R}_{eq}}}+1\] \[\Rightarrow R_{eq}^{2}=2{{R}_{eq}}-1=0\] \[\therefore {{R}_{eq}}=\frac{2+\sqrt{4+4}}{2}=(1+\sqrt{3})\,Q\]You need to login to perform this action.
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