A) 6 and 6
B) 3 and 3
C) 6 and 3
D) 3 and 6
Correct Answer: C
Solution :
\[{{E}_{n}}=\frac{1.36{{Z}^{2}}}{{{n}^{2}}}eV\] If n = 6 and Z = 3 then\[{{E}_{2}}=-\,30.4eV,\]\[{{E}_{3}}=-\,13.6\,eV,\]\[{{E}_{4}}=-\,7.65\,eV,\]\[{{E}_{5}}=-\,4.9\,eV\] and \[{{E}_{6}}=-\,3.4\,eV\] \[\Rightarrow {{E}_{6}}-{{E}_{3}}=10.2eV\]and \[{{E}_{3}}-{{E}_{2}}=16.8\,eV\] Also \[{{E}_{6}}-{{E}_{4}}=4.25\,eV\] and \[{{E}_{4}}-{{E}_{3}}=6.95\,eV\] \[\therefore n=6\]and\[Z=3\]You need to login to perform this action.
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