A) \[0.4\,m/s\]
B) \[0.133\,m/s\]
C) \[0.1\,m/s\]
D) \[0.2\,m/s\]
Correct Answer: C
Solution :
\[{{v}_{T}}=\frac{2{{r}^{2}}({{\rho }_{0}}-{{\rho }_{1}})g}{9\eta }\] \[\frac{0.2}{{{v}_{T}}}=\frac{19.5-1.5}{10.5-1.5}=2\]You need to login to perform this action.
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