A) \[\frac{7}{15}\]
B) \[\frac{8}{15}\]
C) \[\frac{11}{15}\]
D) \[\frac{13}{15}\]
Correct Answer: B
Solution :
Given, \[\Delta =(a+b+c)(a+c-b)\] \[\Rightarrow \Delta =2(s-c).2(s-b)\] ?(1) Also, \[\tan \frac{A}{2}=\sqrt{\frac{(s-b)(s-c)}{s(s-a)}}=\frac{(s-b)(s-c)}{\Delta }=\frac{1}{4}\] So, \[\tan A=\frac{2\tan \frac{A}{2}}{1-{{\tan }^{2}}\frac{A}{2}}=\frac{2\times \frac{1}{4}}{1-{{\left( \frac{1}{4} \right)}^{2}}}=\frac{8}{15}\]You need to login to perform this action.
You will be redirected in
3 sec