A) 1
B) \[\frac{4}{3}\]
C) \[\frac{2}{3}\]
D) \[-2\]
Correct Answer: A
Solution :
\[{{C}_{1}}:{{r}_{1}}=\sqrt{4+25-13}=4\] \[{{C}_{2}}:{{r}_{2}}=\sqrt{36+1-1}=6\] Centre (-2, 5) and (6, -1) \[d=\sqrt{64+36}=10\] Hence circles touch externally. Equation of common internal tangent is \[{{S}_{1}}-{{S}_{2}}=0\] \[16x-12y+12=0\] \[4x+3y+3=0\] y-intercept \[x=0\] \[\Rightarrow y=1\]You need to login to perform this action.
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