A) \[\frac{\sqrt{2}}{\sqrt{3}}\]
B) \[\frac{1}{\sqrt{3}}\]
C) \[\frac{2}{\sqrt{3}}\]
D) \[\frac{\sqrt{3}}{2}\]
Correct Answer: B
Solution :
Bod A, \[mg=2\mu N\] ?(1) Bod B, \[N=T\cos {{60}^{o}}=\frac{T}{2}\] ?(2) \[mg+\mu N=T\sin {{60}^{o}}\] \[=T\frac{\sqrt{3}}{2}\] Putting value of N \[T=\frac{2mg}{\left( \sqrt{3}-\mu \right)}\] From (1) and (2), \[T=\frac{mg}{\mu }\] Comparing \[\frac{2mg}{(\sqrt{3}-\mu )}=\frac{mg}{\mu }\]or\[\mu =\frac{1}{\sqrt{3}}\]You need to login to perform this action.
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