A) 340 min
B) 12min
C) 36min
D) 40 min
Correct Answer: C
Solution :
Energy of 1 mol of photon\[=\frac{{{N}_{A}}hc}{\lambda }\] \[=\frac{6.023\times {{10}^{23}}\times {{10}^{-34}}\times 3\times {{10}^{8}}}{560\times {{10}^{-9}}}=213.69\times {{10}^{3}}J\] Time taken for this energy \[=\frac{213.6\times {{10}^{3}}J}{100\,\,J\,\,{{s}^{-1}}}=2136\,\,\sec \cong 36\,\,\min \]You need to login to perform this action.
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