A) \[0.64\]
B) \[0.48\]
C) \[0.16\]
D) \[0.8\]
Correct Answer: A
Solution :
P (bulb burns) = 0.4 Hence P (circuit breaks = P (A burns and B does not) + P (A does not burn and B burns) = (0.4) (1) + (0.6) (0.4) (If A burns circuit breaks) = 0.4 + 0.24 = 0.64You need to login to perform this action.
You will be redirected in
3 sec