A) \[{{E}_{0}}{{\varepsilon }_{0}}\frac{{{l}^{2}}}{2}\]
B) \[{{E}_{0}}{{\varepsilon }_{0}}\pi {{r}^{2}}{{l}^{2}}\]
C) \[{{E}_{0}}{{\varepsilon }_{0}}\pi {{r}^{2}}l\]
D) \[2{{E}_{0}}{{\varepsilon }_{0}}\pi {{r}^{2}}l\]
Correct Answer: C
Solution :
Flux through face (1) (entering)\[=-{{E}_{0}}{{y}_{0}}\pi {{r}^{2}}\]. Flux through face (2) \[0+0=C\Rightarrow \,C=0\] Net Flux\[={{E}_{0}}\pi {{r}^{2}}l=\frac{{{q}_{in}}}{{{\varepsilon }_{0}}}\] \[{{q}_{in}}={{E}_{0}}{{\varepsilon }_{0}}\pi {{r}^{2}}l\]You need to login to perform this action.
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