A) \[9.08\]
B) \[9.43\]
C) \[11.72\]
D) \[8.73\]
Correct Answer: B
Solution :
\[[N{{H}_{3}}]=0.3\,M[NH_{4}^{+}]=0.2\,\,m\] \[{{K}_{b}}=1.8\times {{10}^{-5}}\] \[{{P}^{OH}}=pKa+\log \frac{[salt]}{[base]}\] \[=4.74+0.3010-0.4771=4.56\] \[{{P}^{H}}=14-4.56=9.436\] \[\Delta {{T}_{b}}=i{{K}_{b}}.m\]You need to login to perform this action.
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