(i) \[F{{e}^{2+}}(g)+2{{e}^{-}}\xrightarrow{{}}Fe(s)\,;\,{{E}^{o}}=-0.44\,V\] |
(ii) \[2{{H}^{+}}(aq)+\frac{1}{2}{{O}_{2}}(g)+2{{e}^{-}}\to {{H}_{2}}O(\ell )\,;\,{{E}^{o}}=+1.23\,V\]the \[{{E}^{o}}\] for the reaction, |
A) \[+1.67\,V\]
B) \[-1.67\,V\]
C) \[+0.79\,V\]
D) \[-0.79\,V\]
Correct Answer: A
Solution :
\[E_{cell}^{^{o}}=E_{OP}^{o}+E_{RP}^{o}=0.44+1.23=1.67V\]You need to login to perform this action.
You will be redirected in
3 sec