A) \[\frac{1}{3}\]
B) \[\frac{2}{3}\]
C) \[\frac{4}{9}\]
D) \[\frac{8}{27}\]
Correct Answer: B
Solution :
\[\left( \frac{\sum\limits_{r=1}^{n}{8{{r}^{3}}}}{\sum\limits_{r=1}^{n}{27{{r}^{3}}}} \right)={{\left( \frac{8}{27} \right)}^{1/3}}=\frac{2}{3}\]
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