A) 1
B) 2
C) 3
D) 4
Correct Answer: C
Solution :
Given, \[\frac{xdy-ydx}{{{y}^{2}}}=dy\Rightarrow d\left( \frac{x}{y} \right)=-dy\Rightarrow \frac{x}{y}=-y+C\] As, \[y(1)=1\Rightarrow C=2\Rightarrow \frac{x}{y}+y=2\] Put\[x=-3,\] we get \[-3+{{y}^{2}}=2y\Rightarrow (y+1)(y-3)=0\] As \[y>0\] As, \[y(x=-3)=3\]You need to login to perform this action.
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