A) 1
B) 2
C) 3
D) 4
Correct Answer: A
Solution :
When electron jumps down from nth state to ground state, number of possible emission lines \[=\frac{n(n-1)}{2}\]When electron jumps down from n^ state to first excited state, number of possible emission lines \[\frac{n(n-1)(n-2)}{2}\]. Let us checkfor n to \[0,\,\,\frac{6(6-1)}{2}\] is not equal to 10. It is not correct. Now check for n to 1, \[\frac{(6-1)(6-2)}{2}\] is equal to 10. It is correct. So, electron comes down to first excited state.
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