A) \[2\times {{10}^{2}}Hz\]
B) \[1.59\times {{10}^{3}}Hz\]
C) \[1.59\times {{10}^{2}}Hz\]
D) \[2.59\times {{10}^{3}}Hz\]
Correct Answer: B
Solution :
\[\omega =\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{2\times {{10}^{-3}}\times 5\times {{10}^{-6}}}}={{10}^{4}}\] \[\omega =2\pi f\] \[f=\frac{\omega }{2\pi }=\frac{10000}{2\times 3.14}=1.59\times {{10}^{3}}\]
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