The reagents X and Y are respectively:
A) \[X=C{{H}_{3}}COCl/AlC{{l}_{3}}\],\[Y=KMn{{O}_{4}}/O{{H}^{\Theta }}/\Delta \], acidification
B) \[X=C{{H}_{3}}C{{H}_{2}}Cl/AlC{{l}_{3}}\],\[Y=Cr{{O}_{3}}/{{H}^{+}}/\Delta \,\therefore \]
C) \[X=C{{H}_{3}}COCl/AlC{{l}_{3}}\],\[Y={{I}_{2}}/O{{H}^{\Theta }}/\Delta \], acidification
D) \[X=KMn{{O}_{4}}/O{{H}^{\Theta }}/\Delta \], acidification,\[Y=C{{H}_{3}}C{{H}_{2}}Cl/AlC{{l}_{3}}\]
Correct Answer: C
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