JEE Main & Advanced Sample Paper JEE Main Sample Paper-32

  • question_answer
    The area bounded by the curve \[y=\frac{\cos x-\sin x}{1+\sin 2x}\]and the x-axis on the interval \[\left[ 0,\frac{\pi }{6} \right]\] , is

    A) \[\sqrt{3}-2\]       

    B)                    \[2-\sqrt{3}\]

    C) \[\sqrt{3}-1\]          

    D)    \[2+\sqrt{3}\]

    Correct Answer: B

    Solution :

    \[\int\limits_{0}^{\pi /6}{\frac{\cos \,x-\sin \,x}{1+\,\sin \,2x}}\,dx=2-\sqrt{3}\]


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