A) \[\frac{27\lambda }{12}\]
B) \[\frac{29\lambda }{12}\]
C) \[\frac{25\lambda }{12}\]
D) \[\frac{31\lambda }{12}\]
Correct Answer: C
Solution :
\[y(x,t)=A\sin (kx-235621t)\] Compare with \[y(x,t)=A\,\sin \,(kx-wt)\] \[\omega =23562\] \[f=\frac{23562}{2\pi }=3750\,Hz\] \[\lambda =\frac{v}{f}=\frac{300}{3750}=0.08\] for \[y=A/2\] and t = 0 \[\frac{A}{2}=A\,\sin \,Kx\,(\sin ce\,K=\frac{2\pi }{\lambda })\] Or \[x=\frac{\lambda }{12}\] Required distance \[=2\lambda +\frac{\lambda }{12}=\frac{25\lambda }{12}\]You need to login to perform this action.
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