A) \[\frac{v_{0}^{2}}{2g}\]
B) \[\frac{2v_{0}^{2}}{g}\]
C) \[\frac{v_{0}^{2}}{g}\]
D) none
Correct Answer: A
Solution :
\[\frac{1}{2}mv_{0}^{2}=mgh\] \[\frac{v_{0}^{2}}{2g}=h=\]Required height
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