A) \[\frac{q}{1+\sqrt{2}}\]
B) \[\frac{-2q}{2+\sqrt{2}}\]
C) \[-2q\]
D) \[+q\]
Correct Answer: B
Solution :
\[U=K\left[ \frac{{{q}^{2}}}{a}+\frac{Qq}{a\sqrt{2}}+\frac{Qq}{a} \right]=0\] For \[Q=\frac{-2q}{2+\sqrt{2}}\]You need to login to perform this action.
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