JEE Main & Advanced Sample Paper JEE Main Sample Paper-32

  • question_answer
    The current is uniformly distributed over the cross-section of a straight cylindrical conductor of radius r. The variation of magnetic field B along a distance x from axis of conductor is shown in the curves. Find the correct option:

    A)        

    B)

    C)      

    D)

    Correct Answer: A

    Solution :

    When \[x<r\] By Ampear's circuital law                 \[B\,.2\pi x={{\mu }_{0.}}\left[ \frac{i}{\pi {{r}^{2}}}\pi {{x}^{2}} \right]\]                 \[B=\frac{{{\mu }_{0}}ix}{2\pi {{r}^{2}}}\] B - x relation is straight line. for x > r By Ampear's law                 \[B.2\pi x={{\mu }_{0}}i\] \[B=\frac{{{\mu }_{0}}i}{2\pi r}\] B- x relation will be rectangular hyperbola. A


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