A) \[l/L\]
B) \[{{l}^{2}}/L\]
C) \[L/l\]
D) \[{{L}^{2}}/l\]
Correct Answer: B
Solution :
Magnetic field at the centre of larger loop \[B=k\frac{I}{L}\] Magnetic flux in the smaller loop \[\phi =B.S=\frac{kI}{L}({{l}^{2}})\] Mutual inductance \[M=\frac{k{{l}^{2}}}{L}\] \[M\,\alpha \,\,\frac{{{l}^{2}}}{L}\]You need to login to perform this action.
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