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JEE Main & Advanced Sample Paper JEE Main Sample Paper-32

  • question_answer
    How much energy an electron in the hydrogen atom in ground state should absorb so that its angular momentum changes by \[\left( h/\pi  \right)\]

    A) 12.1eV      

    B)                                    10.2eV

    C) 12.75 eV       

    D)   13.05 eV

    Correct Answer: A

    Solution :

    \[\Delta L=\frac{h}{\pi }=\,\,\left( \frac{h}{2\pi } \right)\,-\left( \frac{h}{2\pi } \right)\,\,\,so,\,\,n=3\] Electron jumps from ground state to second excited state. So, energy absorbed =13.6-1.51 =12.1 eV


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