question_answer

\[Ph-\underset{o}{\mathop{\underset{||}{\mathop{C}}\,}}\,-\overset{Et}{\mathop{\overset{|}{\mathop{\underset{Me}{\mathop{\underset{|}{\mathop{C}}\,}}\,}}\,}}\,-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}\xrightarrow[\underset{(3)\Delta }{\mathop{(2){{H}^{\oplus }}}}\,]{(1){{\text{l}}_{2}}/O{{H}^{\oplus }}}\] product is:

A) \[Ph-\underset{o}{\mathop{\underset{||}{\mathop{C}}\,}}\,-\overset{Me}{\mathop{\overset{|}{\mathop{\underset{Et}{\mathop{\underset{|}{\mathop{C}}\,}}\,}}\,}}\,-COOH\]

B) \[Ph-\underset{o}{\mathop{\underset{||}{\mathop{C}}\,}}\,-\underset{Et}{\mathop{\underset{|}{\mathop{C}}\,}}\,-Me\]

C) \[Ph-\underset{o}{\mathop{\underset{||}{\mathop{C}}\,}}\,-O-\underset{Et}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-Et\]

D) \[Ph-\underset{o}{\mathop{\underset{||}{\mathop{C}}\,}}\,-\underset{Me}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-OEt\]

Correct Answer: B

Solution :