A) \[10.92\]
B) \[7.90\]
C) \[<7.90\]
D) \[>7.90\]
Correct Answer: C
Solution :
\[Kp=P_{{{H}_{2}}O}^{2}=1.086\,\times {{10}^{-4}}at{{m}^{2}}\] \[{{P}_{{{H}_{2}}O}}\,=1.04\,\times {{10}^{-2}}\,\times 760\,=7.90\,mm\,Hg\]You need to login to perform this action.
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