A) 12.1eV
B) 10.2eV
C) 12.75 eV
D) 13.05 eV
Correct Answer: A
Solution :
\[\Delta L=\frac{h}{\pi }=\,\,\left( \frac{h}{2\pi } \right)\,-\left( \frac{h}{2\pi } \right)\,\,\,so,\,\,n=3\] Electron jumps from ground state to second excited state. So, energy absorbed =13.6-1.51 =12.1 eVYou need to login to perform this action.
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