A) \[\pi 200/In\,2\]
B) \[\pi 100/In\,2\]
C) \[\pi 300/In\,2\]
D) None
Correct Answer: B
Solution :
\[A'=A\,{{e}^{-bt}}\] \[5=10\,{{e}^{-b100\times 2}}\] \[b=\ln 2/200\] \[Q={{\omega }_{0}}\,/2b=2\pi /T2b\]You need to login to perform this action.
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