A) 18
B) 12
C) 10
D) 8
Correct Answer: B
Solution :
For IInd period n = 2 hence I m s 0 0 \[+\frac{1}{2}\,,\,0,\,-\frac{1}{2}\] 1 -1 \[+\frac{1}{2}\,,\,0,\,-\frac{1}{2}\] 0 \[+\frac{1}{2}\,,\,0,\,-\frac{1}{2}\] +1 \[+\frac{1}{2}\,,\,0,\,-\frac{1}{2}\] Hence, total number of elements (total value of spin quantum number) = 12You need to login to perform this action.
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