A) \[9{{x}^{2}}=by\]
B) \[3{{x}^{2}}=2by\]
C) \[9{{x}^{2}}=4by\]
D) \[9{{x}^{2}}=2by\]
Correct Answer: C
Solution :
Let \[A\equiv \,(2bt,\,\,b{{t}^{2}})\,B\equiv \,(-2bt,\,\,b{{t}^{2}})\] be the extremities on the double, ordinate AB. If C (h, k) be it?s trisection point, thenYou need to login to perform this action.
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