A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
\[f(x)\,=\frac{{{e}^{x}}}{{{x}^{2}}}\] Let \[f(x)=\frac{{{e}^{x}}}{{{x}^{2}}},f'(x)=\frac{(x-2)\,{{e}^{x}}}{{{x}^{3}}}\] So, from above graph, \[c\,>\,\frac{{{e}^{2}}}{4}\] So, \[{{c}_{\min }}\,=2\]You need to login to perform this action.
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