A) 1
B) 2
C) 3
D) 4
Correct Answer: C
Solution :
Given \[\frac{d}{dx}\,\left( x\frac{dy}{dx} \right)=\,\ln \,x\] \[\Rightarrow \,x\frac{dy}{dx}=x\,\ln \,\,x-x+C\] Now \[y'(1)=-1,\] so \[-1=0-1+C\,\Rightarrow \,C=0\] \[\therefore \,\frac{dy}{dx}\,=\ln \,x-1\] Hence \[{{\left. \frac{{{d}^{2}}y}{d{{x}^{2}}} \right]}_{x=\frac{1}{3}}}=\frac{1}{x}=3\]You need to login to perform this action.
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