A) \[2m{{r}^{2}}\]
B) \[\frac{m{{r}^{2}}}{2}\]
C) \[\frac{3}{2}m{{r}^{2}}\]
D) \[m{{r}^{2}}\]
Correct Answer: C
Solution :
\[\therefore {{I}_{x}}\,+{{I}_{y}}\,={{I}_{z}}\] \[{{I}_{x}}={{I}_{y}}\] \[\Rightarrow \,\,2{{I}_{x}}\,={{I}_{z}}\] \[\Rightarrow \,{{I}_{x}}\,=\frac{{{I}_{z}}}{2}\,=\frac{m{{r}^{2}}}{2}\] Require \[{{I}_{PQ}}\,={{I}_{x}}\,+m{{r}^{2}}\,=\frac{3}{2}\,m{{r}^{2}}\]You need to login to perform this action.
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