A) 24000V
B) 9600V
C) 12000V
D) 3000V
Correct Answer: D
Solution :
\[\lambda =\frac{h}{P}\,=\frac{h}{\sqrt{2km}}\,=\frac{h}{\sqrt{2qVm}}\] \[\,\because \,\,{{\lambda }_{1}}={{\lambda }_{2}}\] \[\Rightarrow \,\,{{q}_{1}}{{m}_{1}}{{V}_{1}}={{q}_{2}}{{m}_{2}}{{V}_{2}}\] \[{{V}_{2}}\,=\frac{{{q}_{1}}}{{{q}_{2}}}\,\frac{{{m}_{1}}}{{{m}_{2}}}\,{{V}_{1}}\,=\frac{e}{2e}\frac{m}{4m}\,\times 24000\] \[\Rightarrow \,{{V}_{2}}\,=\,3000\,V\].
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