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JEE Main & Advanced Sample Paper JEE Main Sample Paper-33

  • question_answer
    A light emitting diode has a voltage drop of 2 volt across it and passes a current of 10 mA when it operates with 6 volt battery through a limiting resistor R. The value of R is:

    A)  \[40\Omega \]           

    B)                     \[4k\Omega \]

    C)  \[200\Omega \]              

    D)     \[400\Omega \]

    Correct Answer: D

    Solution :

    \[R=\frac{V}{I}=\frac{6-2}{10\times {{10}^{-3}}}\,=400\,\Omega \]


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