A) 2A
B) 0.8 A
C) 5A
D) 0.1A
Correct Answer: B
Solution :
When c is removed \[\tan \phi =\tan 45=\frac{{{X}_{L}}}{R}\] \[{{X}_{L}}=R\] When L is removed \[\tan \phi =\frac{1}{2}\,=\frac{{{X}_{C}}}{R}\] \[{{X}_{C}}=\frac{R}{2}\] \[Z=\,\sqrt{{{(50\sqrt{5})}^{2}}+{{(100\,\sqrt{5})}^{2}}}\] \[{{i}_{rms}}\,=\frac{{{v}_{rms}}}{Z}\,=\frac{200}{60\times 5}\,=0.8\,A\]You need to login to perform this action.
You will be redirected in
3 sec